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Fix Non Recursive Depth First Search #2207

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Sep 11, 2020
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33 changes: 12 additions & 21 deletions graphs/depth_first_search.py
Original file line number Diff line number Diff line change
@@ -1,24 +1,12 @@
"""The DFS function simply calls itself recursively for every unvisited child of
its argument. We can emulate that behaviour precisely using a stack of iterators.
Instead of recursively calling with a node, we'll push an iterator to the node's
children onto the iterator stack. When the iterator at the top of the stack
terminates, we'll pop it off the stack.

Pseudocode:
all nodes initially unexplored
mark s as explored
for every edge (s, v):
if v unexplored:
DFS(G, v)
"""
from typing import Dict, Set
"""Non recursive implementation of a DFS algorithm."""

from typing import Set, Dict


def depth_first_search(graph: Dict, start: str) -> Set[int]:
"""Depth First Search on Graph

:param graph: directed graph in dictionary format
:param vertex: starting vectex as a string
:param vertex: starting vertex as a string
:returns: the trace of the search
>>> G = { "A": ["B", "C", "D"], "B": ["A", "D", "E"],
... "C": ["A", "F"], "D": ["B", "D"], "E": ["B", "F"],
Expand All @@ -31,13 +19,16 @@ def depth_first_search(graph: Dict, start: str) -> Set[int]:
True
"""
explored, stack = set(start), [start]

while stack:
v = stack.pop()
# one difference from BFS is to pop last element here instead of first one
for w in graph[v]:
if w not in explored:
explored.add(w)
stack.append(w)
explored.add(v)
# Differences from BFS:
# 1) pop last element instead of first one
# 2) add adjacent elements to stack without exploring them
for adj in reversed(graph[v]):
if adj not in explored:
stack.append(adj)
return explored


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