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This would return Axis[:].difference(Group).
For example,
>>> a = Axis('a=a0..a4') >>> ~a['a0,a3'] a['a1', 'a2', 'a4']
The text was updated successfully, but these errors were encountered:
Easy but not possible with current group API (because ~ is already defined). We need #23.
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removed easy label to avoid a new contributor trying to tackle this before #23 is done
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This would return Axis[:].difference(Group).
For example,
The text was updated successfully, but these errors were encountered: