FindTheCelebrity.java

/* (C) 2024 YourCompanyName */
package array;

import java.util.HashMap;
import java.util.HashSet;
import java.util.Map;
import java.util.Set;

/**
 * Created by gouthamvidyapradhan on 25/11/2017.
 *
 * <p>Suppose you are at a party with n people (labeled from 0 to n - 1) and among them, there may
 * exist one celebrity. The definition of a celebrity is that all the other n - 1 people know
 * him/her but he/she does not know any of them.
 *
 * <p>Now you want to find out who the celebrity is or verify that there is not one. The only thing
 * you are allowed to do is to ask questions like: "Hi, A. Do you know B?" to get information of
 * whether A knows B. You need to find out the celebrity (or verify there is not one) by asking as
 * few questions as possible (in the asymptotic sense).
 *
 * <p>You are given a helper function bool knows(a, b) which tells you whether A knows B. Implement
 * a function int findCelebrity(n), your function should minimize the number of calls to knows.
 *
 * <p>Note: There will be exactly one celebrity if he/she is in the party. Return the celebrity's
 * label if there is a celebrity in the party. If there is no celebrity, return -1.
 */
public class FindTheCelebrity {

  private static Map<Integer, Set<Integer>> map = new HashMap<>();

  /**
   * Main method
   *
   * @param args
   */
  public static void main(String[] args) {
    // initialize relationship
    map.put(0, new HashSet<>());
    map.put(1, new HashSet<>());
    map.put(2, new HashSet<>());
    map.put(3, new HashSet<>());
    map.put(4, new HashSet<>());
    map.put(5, new HashSet<>());
    map.put(6, new HashSet<>());
    map.get(0).add(3);
    map.get(0).add(1);
    map.get(0).add(2);
    map.get(0).add(4);
    map.get(0).add(5);
    map.get(0).add(6);

    map.get(1).add(0);
    map.get(1).add(3);
    map.get(1).add(2);

    map.get(2).add(1);
    map.get(2).add(3);
    map.get(2).add(4);

    map.get(4).add(2);
    map.get(4).add(3);
    map.get(4).add(5);

    map.get(5).add(4);
    map.get(5).add(3);
    map.get(5).add(6);

    map.get(6).add(5);
    map.get(6).add(3);
    map.get(6).add(0);

    System.out.println(new FindTheCelebrity().findCelebrity(0));
  }

  /**
   * Find celebrity
   *
   * @param n
   * @return
   */
  public int findCelebrity(int n) {
    int candidate = -1, i = 0, next = 1;
    while (i < n) {
      if (next >= n) break;
      if (knows(i, next) && !knows(next, i)) {
        i = next;
        next = i + 1;
      } else if ((!knows(i, next) && !knows(next, i)) || (knows(i, next) && knows(next, i))) {
        i = next + 1;
        next = i + 1;
      } else {
        next++;
      }
      candidate = i;
    }
    if (candidate == -1 || candidate >= n) return -1;
    for (int j = 0; j < candidate; j++) {
      if (!knows(j, candidate) || knows(candidate, j)) {
        candidate = -1;
        break;
      }
    }
    return candidate;
  }

  private boolean knows(int a, int b) {
    return map.get(a).contains(b);
  }
}